(2x+3)^2=-9x+27

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Solution for (2x+3)^2=-9x+27 equation: 



(2x+3)^2=-9x+27

We move all terms to the left:

(2x+3)^2-(-9x+27)=0

We get rid of parentheses

(2x+3)^2+9x-27=0

We add all the numbers together, and all the variables

9x+(2x+3)^2-27=0

We move all terms containing x to the left, all other terms to the right

9x+(2x+3)^2=27

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